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Each hydrogen atom is excited by giving ...

Each hydrogen atom is excited by giving 10.2eV. The maximum number of spectral lines in the emission is equal to

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
`E_2 - E_1 = 10.2 ev`, so electron is excited to second orbit, therefore no. of spectral lines `= (n(n-1) )/(2)`
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