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What is the lowest energy of the spectra...

What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series?
(h = Planck's constant, c = velocity of light, R = Rydberg's constant).

A

`(5 hc R)/(36)`

B

`(4 hc R)/(3)`

C

`(3hc R)/(4)`

D

`(7 hc R)/(144)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta E = "Rhc" [ (1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
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