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The Ratio of m^(th) to n^(th) wavelength...

The Ratio of `m^(th)` to `n^(th)` wavelength of Lyman series in H-spectrum is equal to

A

`(lambda_(m))/(lambda_(n)) = ((m^2 -1) xx n^2)/((n^2 -1 ) xx m^2)`

B

`(lambda_(m))/(lambda_(n)) = ((n^2 - 1) xx m^2)/((m^2 -1 ) xx n^2)`

C

`(lambda_m)/(lambda_n) = (((m+1)^(2)-1)/(m+1)^(2)-1) `

D

`(lambda_m)/(lambda_n) = ((n+1)^(2) )/((m+1)^(2)) xx ((m+1)^(2)-1)/((n+1)^(2) -1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`bar(v) = (1)/(lambda) = R[ (1)/(n_(1)^(2) ) - (1)/(n_(2)^(2))]`
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