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The energies E1 and E2 of two radiations...

The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.

A

`lambda_1 = (1)/(2) lambda_2`

B

`lambda_1 = lambda_2`

C

`lambda_1 = 2 lambda_2`

D

`lambda_1 = 4 lambda_2`

Text Solution

Verified by Experts

The correct Answer is:
C
`(E_1)/(E_2) = (lambda_2)/(lambda_1)`
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