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A dye absorbs light of lambda = 4530 Å ...

A dye absorbs light of `lambda` = `4530` Å and then fluorescence light of `5080` Å. Assuming that under given condition `47%` of the absorbed energy is re-emitted out as flourescence, calculate the ratio of quanta emitted out to the number of quanta absorbed.

A

`0.527`

B

`1.5`

C

`52.7`

D

`3`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = (Nhc)/(lambda) , (E_1)/(E_2) = (lambda_2)/(lambda_1)`
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