The spin-only magnetic moment [in units of Bohr magneton, `(mu_(B)` of `Ni^(2+))` in aqueous solution would be (atomic number of `Ni=28)`
A
2.84
B
4.9
C
0
D
1.73
Text Solution
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The correct Answer is:
A
`mu_(B) = sqrt(n(n+2) ) Ni^(+2) = 3d^(8)` Number of unpaired electrons (n) = 2
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Assertion (A): The "spin only” magnetic moment [in units of Bohr magneton, ( mu_(B) )] of Ni^(2+) in aqueous solution would be (atomic number Ni= 28) 2.84 BM Reason (R): The metal ion has 2 unpaired electrons
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