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For a weak acid (alpha is very small)...

For a weak acid (`alpha` is very small)

A

`K_(a)=C.alpha^(2)`

B

`alpha=sqrt((K_(a))/(C))`

C

`[H^(+)]=Calpha`

D

All the above

Text Solution

Verified by Experts

The correct Answer is:
D
`k_(a)=calpha^(2),alpha=sqrt((k_(a))/(c)),[H^(+)]=calpha`
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