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What will be the pH of a solution formed...

What will be the pH of a solution formed by mixing `40cm^(2)` of `0.1 M HCl` with `10 cm^(3)` of `0.45 M NaOH`

A

10

B

8

C

5

D

12

Text Solution

Verified by Experts

The correct Answer is:
D

No of m eq of `H^(+)` ions `=40xx0.1=4`
No of m.e of OH ions `=10xx0.45=4.5`
`[O^(-)H]=(4.5-4)/(50)=(0.5)/(50)=0.01`
`p^(OH)=-10g10^(-2),p^(OH)=2`
`p^(H)=12`
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