Home
Class 11
CHEMISTRY
The solubility product of a salt having ...

The solubility product of a salt having general formula `MX_(2)` in water is `4xx10^(-12)`. The concentration of `M^(2+) ions` in the aqueous solution of the salt is:

A

`4xx10^(-10)M`

B

`1.6xx10^(-4)M`

C

`1xx10^(-4)M`

D

`2xx10^(-6)M`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(SP)=(4s^(3))`
Promotional Banner

Topper's Solved these Questions

  • ACIDS & BASES

    NARAYNA|Exercise EXERCISE-I (H.W) (IONISATION OF ACIDS & BASES, DEGREE OF IONISATION & Kw)|7 Videos

  • ACIDS & BASES

    NARAYNA|Exercise EXERCISE-I (H.W) (SALT HYDROLYSIS & BUFFERS)|23 Videos

  • ACIDS & BASES

    NARAYNA|Exercise EXERCISE-I (C.W) ( BUFFER SOLUTION )|11 Videos

  • 14TH GROUP ELEMENTS

    NARAYNA|Exercise Subjective Questions|6 Videos

  • ALKANES

    NARAYNA|Exercise Integer Answer Type|7 Videos

Similar Questions

Explore conceptually related problems

The solubility product of a sparingly soluble salt BA_(2) is 4xx10^(-12) . The solubility of BA_(2) is

The solubility proudct of a salt having formula M_(2)X_(3) is 2.2 xx 10^(-20) . If the solubility of an another salt having formula M_(2)X is twice the molar solubility of M_(2)X_(3) , the solubility product of M_(2)X is

The solubility product of Ag CrO_(4) is 32xx10^(-12). What is the concentration of CrO_(4)^(2-) ions in that solution ?

The solubility product of silver chromate is 4xx10^(-12) . The molar solubility of the salt is

The solubility product of a sparingly soluble salt AX_(2) is 3.2xx10^(-11) . Its solubility (in mo//L ) is

The solubility of a springly soluble salt AB_(2) in water is 1.0xx10^(-5) mol L^(-1) . Its solubility product is: