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In the following reaction, AgCl + NaI ...

In the following reaction,
`AgCl + NaI hArr NaCl + AgI`. As `NaI` is added, the equilibrium is shifted towards right giving more `Ag` I precipitate , because

A

Both AgCl and Agl are sparingly soluble

B

The `K_(sp)` of Agl is lower than `K_(sp)` of AgCl

C

The `K_(sp)` of AgI is higher than `K_(sp)` of AgCl

D

Both AgCl and AgI have same solubility product

Text Solution

Verified by Experts

The correct Answer is:
B
`k_(sp)AgIltK_(sp)AgCl`
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