Calculate the pH of `10^(-10)` M NaOH solution.

Options

A. 7.04
B. 8
C. 6
D. 6.96

Answer

A

Explanation

`[OH^(-)]` from `NaOH=10^(-8)M`
Total `[OH^(-)]=10^(-7)+10^(-7)`
`[OH^(-)]=1.1xx10^(-7)" "P^(OH)=-log_(10)[OH^(-)]`
`=-log_(10)1.1xx10^(-7)=6.96`
`P^(H)+P^(OH)=14" "P^(H)=14-6.96=7.04`