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75 mL of 0.2 M HCl is mixed with 25 mL o...

`75 mL` of `0.2 M HCl` is mixed with `25 mL` of `1 M HCl`. To this solution `300 mL` of distilled water is added. What is the pH of the resultant solution ?

A

1

B

2

C

4

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
A
`N=(V_(1)N_(1)+V_(2)N_(2))/("Total volume")=(0.2xx75+1xx25)/(75+25+300)=0.1`
`P^(H)=-log_(10)[H^(+)]=-log_(10)10^(-1)`
`:.P^(H)=1`
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