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Equal volumes of two solutions with P^(H...

Equal volumes of two solutions with `P^(H) = 3` and `P^(H) = 11` are mixed. Then `P^(H)` of resulting solution is

A

8

B

7

C

6

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
An acid and base having equal volumes and equal strength when mixed to give neutral solution.
`("solution-1(acid)")/(P^(H)=3),("solution-2(base)")/(P^(H)=11(or)P^(OH)=3)`
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