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When 1 ml of 0.1 N HCI is added to 1 lit...

When `1 ml` of `0.1 N HCI` is added to `1` litre of a solution of `pH` value `4`, the pH will be nearly

A

5

B

4.477

C

3

D

3.699

Text Solution

Verified by Experts

The correct Answer is:
D
`[H^(+)]=(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))`
`[H^(+)]=(0.1xx1+1000xx10^(-4))/(1000)`
`=0.0002=2xx10^(-4)`
`P^(H)=-log_(10)2xx10^(-4)=4-0.3010=3.699`
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