Home
Class 11
CHEMISTRY
A 0.001 M ammonia solution is 5% ionized...

A 0.001 M ammonia solution is `5%` ionized the concentration of `OH^(-)` ion is

A

0.005 M

B

0.0001 M

C

0.0005 M

D

0.05 M

Text Solution

Verified by Experts

The correct Answer is:
C

`[OH^(-)]=Calpha=Cxx(%)/(100)=0.01xx(5)/(100)=0.0005`
Promotional Banner

Similar Questions

Explore conceptually related problems

A 0.01 M ammonia solution is 5% ionised. Its pH will be

In aqueous solution concentration of H^(+) ions is 10^(-4) mol/1. If equal volume of water is added to the solution, then the concentration of OH^(-) ion in mol/ dm^(3) is

At 298 K a 0.01 M CH_(3)COOH solution is 1.34% ionized. The ionization constant K_(a) for acetic acid will be

0.05 M ammonium hydroxide solution is dissolved in 0.001 M ammonium chloride solution. What will be the OH^(-) ion concentration of this solution ? (K_(b) (NH_(4) OH) = 1.8 xx 10^(-5)

The ionization constant of acetic acid 1.74xx10^(-5) . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH .

A weak mono acidic base is 5% ionized in 0.01 M solution. The Hydroxide ion concentration in the solution is