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50 mL of H(2)O is added to 50 mL of 1 xx...

50 mL of `H_(2)O` is added to `50 mL` of `1 xx 10^(-3)M` barium hydroxide solution. What is the pH of the resulting solution?

A

3

B

3.3

C

11

D

11.7

Text Solution

Verified by Experts

The correct Answer is:
C
`V_(1)N_(1)=V_(2)N_(2)`
`100xN=50x10^(-3)x2`
`100xN=50xx10^(-3)xx2`
`N=10^(-3)pOH=3,pH=11`
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