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The solubility of Ag(2)CrO(4) is 2 xx 10...

The solubility of `Ag_(2)CrO_(4)` is `2 xx 10^(-2) "mol"//"lit"` its solubility product is

A

`3.2xx10^(-5)`

B

`32xx10^(-8)`

C

`16xx10^(-8)`

D

`3.32xx10^(-10)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Ag_(2)CrO_(4) to 2Ag^(+)CrO_(4)^(2-)`
`KSp=(2S)^(2)S=4S^(4)`
`=(2x10^(-2))^(3)=4x8x10^(-6)=3.2x10^(-5)`
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