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The molar solubility of PbI(2) in 0.2 M ...

The molar solubility of `PbI_(2)` in `0.2 M Pb(NO_(3))_(2)` solution in terms of solubility product, `K_(sp)`

A

`(K_(sp)//10.8)^(1//3)`

B

`(K_(sp)//3.6)^(1//3)`

C

`(K_(sp)//10.8)^(1//4)`

D

`(K_(sp)//0.4)^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(0.4)(M(OH)_(3))underset(3S)(hArr)M^(+3)+3OH^(-)`
because `[M^(3+)]=[MX_(3)]`,
`:.0.4x(3S)^(3)=K_(sp)`
`S=((K_(sp))/(10.8))`
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