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The P^(H) of a sample of H(2)SO(4) is 1....

The `P^(H)` of a sample of `H_(2)SO_(4)` is `1.3979`. The percentage of the solution is `73.5% (w//w)`, the density of the solution is

A

`2.66xx10^(-3)g//c c`

B

`5.32xx10^(-3)g//c c`

C

`1.33xx10^(-3)g//c c`

D

`0.01 g//c c`

Text Solution

Verified by Experts

The correct Answer is:
A

`[H^(+)]`= Normality of `H_(2)SO_(4)`
`=10^(-2) xx` anti log of `0.6021=4xx10^(-2)`
But Normality `=(%xxxx10)/(Eq. Wt)`
`rArr 4xx10^(-2)=(73.5xxdxx10)/(49)`
`:.d=2.66xx10^(3)gm/c c`
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