Solubility of `MX_(2)` type electrolytes is `0.5xx10^(-4) mol//L`, then find out `K_(sp)` of electrolytes.

Options

A. `5xx10^(-12)`
B. `25xx10^(-10)`
C. `1xx10^(-13)`
D. `5xx10^(-13)`

Answer

D

Explanation

`underset("Solubility"0.5x10^(-4)M)(M_(2)X_(2)) hArr underset(0.5x10^(-4)M)(M^(+))+underset(2x0.5xx10^(-4)M)(X^(2-))`
(ON 100% ionisation)
`:.K_(sp)"of" MX_(2)=[M^(+)][X^(-)]^(2)`
`=(0.5x10^(-4))(1.0x10^(-4))^(2)=0.5x10^(-12)=5x10^(-13)`