The hydrogen ion concentration of a `10^(-8) M HCl` aqueous soultion at `298 K(K_(w)=10^(-14))` is

Options

A. `1.0xx10^(-6)M`
B. `1.0525xx10^(-7)M`
C. `9.525xx10^(-8)M`
D. `1.0xx10^(-10)M`

Answer

B

Explanation

In aqueous solution of `10^(-8) M HCl,[H^(+)]` is based upon the concentration of `H^(+)` ion of `10^(-8) M CHl` and concetration of `H^(+)` ion of `H^(+)` ion of water.
`K_(w) "of" H_(2)O=10^(-4)=[H^(+)] [OH^(-)] or [H^(+)] or [H^(+)]=10^(-7)M` (due to its neutral behaviour So, in aqueous solution of `10^(-8) M HCl`
`[H^(+)]=[H^(+)] "of" HCl +[H^(+)]` of water
`=10^(-8)+10^(-7)=11x10^(-8)M`
`~~1.10x10^(-7)M`