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Calculate the pOH of solution at 25^(@)C...

Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

A

4

B

9

C

1

D

7

Text Solution

Verified by Experts

The correct Answer is:
A
Since `[H_(3)O^(+)]=1x10^(-10)M "at" 25^(@)C`
`[H_(3)O^(+)][OH^(-)]=10^(-14)`
`[OH^(-)]=(10^(-4))/(10^(-10))=10^(-4)`
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NARAYNA-ACIDS & BASES-EXERCISE-III
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