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A monoprotic acid in 0.1 M solution has...

A monoprotic acid in `0.1 M` solution has `K_(a)=1.0xx10^(-5)`. The degree of dissociation for acid is

A

`1.0%`

B

`99.9%`

C

`0.1%`

D

0.99

Text Solution

Verified by Experts

The correct Answer is:
A

`K_(a)=c alpha^(2) or 1.0 x 10^(-5)=0.1 x alpha^(2)`
`:.alpha=10^(-2) or 1%`
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