The `K_(sp)` of `Ag_(2)CrO_(4),AgCl,AgBr` and AgI are respectively, `1.1xx10^(-12),1.8xx10^(-10),5.0xx10^(-13),8.3xx10^(-17)`. Which one of the following salts will precipitate last if `AgNO_(3)` solution is added to the solution containing equal moles of NaCl,NaBr,NaI and `Na_(2)CrO_(4)` ?

Options

A. AgBr
B. `Ag_(2)CrO_(4)`
C. Agl
D. AgCl

Answer

B

Explanation

Salt `K_(sp)` Solubility
`Ag_(2)CrO_(4)" "1.1xx10^(-12)=4s^(3)" "s=3sqrt((K_(sp))/(4))0.65xx10^(-4)`
`AgC" "1.8xx10^(-10)=s^(2)" "s=sqrt(K_(sp))1.35xx10^(-5)`
`AgBr" "5xx10^(-13)=s^(2)" "s=sqrt(K_(sp))0.71xx10^(-6)`
`Agl" "8.3xx10^(-14)=s^(2)" "s=3sqrt(K_(sp))0.9xx10^(-8)`
Solubility of `Ag_(2)CrO_(4)` is highest, thus it will be precipitated at last