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M^(+3) ion loses 3e^(-). Its oxidation n...

`M^(+3)` ion loses `3e^(-).` Its oxidation number will be

A

0

B

`+3`

C

`+6`

D

`-3`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the oxidation number of the ion \( M^{+3} \) after it loses 3 electrons, we can follow these steps: ### Step 1: Identify the initial oxidation state The ion \( M^{+3} \) has an initial oxidation state of +3. This means that it has lost 3 electrons compared to its neutral state. **Hint:** The oxidation state of an ion is indicated by its charge. A \( +3 \) charge means it has lost 3 electrons. ### Step 2: Understand the process of losing electrons When an ion loses electrons, its oxidation state increases. This is because losing negatively charged electrons makes the ion more positive. **Hint:** Remember that losing electrons leads to an increase in oxidation state. ### Step 3: Calculate the new oxidation state Since \( M^{+3} \) loses 3 electrons, we add 3 to its current oxidation state: \[ +3 + 3 = +6 \] **Hint:** To find the new oxidation state after losing electrons, simply add the number of electrons lost to the initial oxidation state. ### Step 4: Conclusion The oxidation number of the ion \( M \) after losing 3 electrons will be \( +6 \). **Final Answer:** The oxidation number of the \( M \) ion will be \( +6 \). ---
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