Of the following outer electronic configurations of atoms, the highest oxidation state is achieved by which one of them ?

Options

A. `(n-1)d^(8) ns^(2)`
B. `(n-1) d^(5) ns^(2)`
C. `(n-1)d^(3) ns^(2)`
D. `(n-1)d^(5) ns^(1)`

Answer

B

Explanation

Chromite of chrome iron ore is `FeCr_2O_4`. Its actual composition is `FeO. Cr_2O_3" In "` FeO, oxidation state of Fe is calculated as `x+(-2)=0 rArr x= +2` Similarly, in `Cr_2O_(3)` the oxidation state of Cr is `2 xx x+(-2) xx 3=0`
2x=+6 x=+3