For the reaction
`M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2)`
if `1 "mol of" MnO_(4)^(ө)` oxidises `1.67 "mol of" M^(x+) "to" MO_(3)^(ө)`, then the value of `x` in the reaction is

Options

A. 5
B. 3
C. 2
D. 1

Explanation

`5e^(-) +MnO_(4)^(-) to Mn^(2+)`
`M^(x+) to MO_(3)^(-) +(5-x)`
x-6=-1
x=5
Equivalent of `MnO_(4)^(-)=" Equivalent of M"^(x+)`
1 mol x 5=1.67 mol x(5-x)
x=2