The number of moles of `K_(2)Cr_(2)O_(7)` reduced by `1 mol` of `Sn^(2+)` ions is

Options

A. `1//6`
B. `1//3`
C. `2//3`
D. 1

Explanation

Eq of `Cr_(2)O_(7)^(2-) -=" Eq of "Sn^(2+)`
(n=6) (n=2) `1/6 mol=1/2 mol`
`1/3 mol Cr_(2)O_(7)^(2-)="1 mol of "Sn^(2+)`