In alkaline medium, `ClO_(2)` oxidises `H_(2)O_(2) "to" O_(2)` and is itself reduced to `Cl^(ө)`. How many moles of `H_(2)O_(2)` are oxidised by `1 "mol of " ClO_(2)` ?

Options

A. 1
B. `3//2`
C. `5//2`
D. `7//2`

Explanation

`5e^(-)+ClO_(2) to Cl^(-)`
Eq of `ClO_(2)="Eq "H_(2)O_(2)`
(n=5) (n=2)
`1/5 mol=1/2 mol`
1 mole of `ClO_(2)=1/5" mol of "H_(2)O_(2)`