Molarity of `H_(2)SO_(4)` is 18 M. Its density is `1.8 g//cm^(3)`,hence molality is:

Options

A. 400 molal
B. 500 molal
C. 600 molal
D. 800 molal

Explanation

Molality and molarity are related by equation,
`m=(1000 M)/((1000 d-Mm_(1)))`
where M is molar mass and `m_(1)` is mass
`m=(1000xx18)/(1000d xx 1.8-18xx98)=500` molal.