One liter of sea water weighs 1050 grams and contains `6 xx 10^(-3)g` of dissolved oxygen gas. Calculate the concentration of the dissolved oxygen in ppm.

Options

A. 68 ppm
B. 5.8 ppm
C. 580 ppm
D. 0.58 ppm

Explanation

Mass of `O_(2)` in mg
`= 6xx10^(-3)g xx 10^(3)mg//g = 6 mg`
ppm of `O_(2)` in 1030 g sea water
`=("Mass of " O_(2)" in mg")/("Mass of sea water in kg")=(6)/((1030//1000)kg)`
`= (6xx1000)/(1030)=5.8` ppm