An electrolyte `XY_(2)` is 40% ionized. Calculate van't Hoff factor

Explanation

To calculate the van't Hoff factor (i) for the electrolyte \( XY_2 \) which is 40% ionized, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrolyte and its Ionization**:
The electrolyte \( XY_2 \) dissociates into ions as follows:
\[
XY_2 \rightarrow X^{2+} + 2Y^{-}
...