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Number of moles of solute dissolved in 1...

Number of moles of solute dissolved in 1000 g. of the solvent is called

A

Molarity

B

Molality

C

Formality

D

Normality

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To solve the question "Number of moles of solute dissolved in 1000 g of the solvent is called," we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept**: We need to identify the term that describes the concentration of a solute in a solvent, specifically in relation to the mass of the solvent. 2. **Identify the Mass of Solvent**: The question specifies that the mass of the solvent is 1000 grams. This is equivalent to 1 kilogram (since 1000 g = 1 kg). 3. **Define the Term**: The concentration term that describes the number of moles of solute per kilogram of solvent is known as "molality." 4. **Mathematical Expression**: Molality (m) is mathematically expressed as: \[ m = \frac{n}{W} \] where: - \( m \) = molality - \( n \) = number of moles of solute - \( W \) = weight of the solvent in kilograms (kg) 5. **Conclusion**: Therefore, the answer to the question is that the number of moles of solute dissolved in 1000 g of the solvent is called "molality." ### Final Answer: The number of moles of solute dissolved in 1000 g of the solvent is called **molality**. ---

To solve the question "Number of moles of solute dissolved in 1000 g of the solvent is called," we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept**: We need to identify the term that describes the concentration of a solute in a solvent, specifically in relation to the mass of the solvent. 2. **Identify the Mass of Solvent**: The question specifies that the mass of the solvent is 1000 grams. This is equivalent to 1 kilogram (since 1000 g = 1 kg). ...
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In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton 1.57 g of oxalic acid (COOH)_(2)xH_(2)O are dissolved in water and the volume is made upto 250 mL. On titrating 6.68 mL of this solution requires 25 mL of N/15 NaOH solution for complete neutralisation. The value of x is :

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The mole fraction of glycerine C_(3)H_(5)(OH)_(3) in a solution containing 36 g of water and 46 g of glycerine is :

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The unit of molarity are

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The molality of pure water is :

Assertion: Lowering in vapour pressure is not a colligative property. Reason: Lowering of vapour pressure of a solvent depends on the number of moles of the solute dissolved in given amount of the solvent at a given temperature.

Number of moles of solute dissolved per litre of solution is

The concentrations of soluitons can be expressed in number of ways , viz : mass fraction of solute (or mass percent), Molar concentration (Molarity ) and Molal concentration (molality). These terms are known as concentration terms and also they are related with each otehr i.e., knowing one concentration terms for the solution, we can find other concentration terms also. the definition of different cencentration terms are given below: Molarity : It is number of moles of solute present in one litre of the solution. Molality : It is the number of moles of solute present in one kg of the solvent. Mole fraction =("Mole of solute")/("Moles of solute" + "Moles of solvent") If molality of the solution is given as a, then mole fraction of the solute can be calculated by Mole Fraction =(a)/(a+(100)/(M_("solvent"))),=(axxM_("solvent"))/((a xx M_("solvent")+1000)0 where a=molality and M_("solvent") =Molar mass of solvent We can change : Mole fraction hArr Molality hArr Molarity What is the mole fraction of the solute?

The concentrations of soluitons can be expressed in number of ways , viz : mass fraction of solute (or mass percent), Molar concentration (Molarity ) and Molal concentration (molality). These terms are known as concentration terms and also they are related with each otehr i.e., knowing one concentration terms for the solution, we can find other concentration terms also. the definition of different cencentration terms are given below: Molarity : It is number of moles of solute present in one litre of the solution. Molality : It is the number of moles of solute present in one kg of the solvent. Mole fraction =("Mole of solute")/("Moles of solute" + "Moles of solvent") If molality of the solution is given as a, then mole fraction of the solute can be calculated by Mole Fraction =(a)/(a+(100)/(M_("solvent"))),=(axxM_("solvent"))/((a xx M_("solvent")+1000)0 where a=molality and M_("solvent") =Molar mass of solvent We can change : Mole fraction hArr Molality hArr Molarity Percentage (weight/vol) of NaCl persent in the solution is :

The concentrations of soluitons can be expressed in number of ways , viz : mass fraction of solute (or mass percent), Molar concentration (Molarity ) and Molal concentration (molality). These terms are known as concentration terms and also they are related with each otehr i.e., knowing one concentration terms for the solution, we can find other concentration terms also. the definition of different cencentration terms are given below: Molarity : It is number of moles of solute present in one litre of the solution. Molality : It is the number of moles of solute present in one kg of the solvent. Mole fraction =("Mole of solute")/("Moles of solute" + "Moles of solvent") If molality of the solution is given as a, then mole fraction of the solute can be calculated by Mole Fraction =(a)/(a+(100)/(M_("solvent"))),=(axxM_("solvent"))/((a xx M_("solvent")+1000)0 where a=molality and M_("solvent") =Molar mass of solvent We can change : Mole fraction hArr Molality hArr Molarity What is the molality of the above solution?

NARAYNA-SOLUTIONS & COLLIGATIVE PROPERTIES -EXERCISE : 1 (C.W)
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  5. Which of the following is correct ?

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