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A solution of known normality is diluted...

A solution of known normality is diluted to two times. Which of the following changes during dilution ?

A

Equivalent of solute

B

Moles of solute

C

Milli equivalent or milli moles of solute

D

Normality of solute

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The correct Answer is:
To solve the question regarding the changes that occur when a solution of known normality is diluted to two times its original volume, we can follow these steps: ### Step 1: Understand the Concept of Normality Normality (N) is defined as the number of equivalents of solute per liter of solution. It can be expressed mathematically as: \[ \text{Normality (N)} = \frac{\text{Number of equivalents}}{\text{Volume of solution in liters}} \] ### Step 2: Analyze the Dilution Process When a solution is diluted, the amount of solute (in equivalents) remains constant, but the volume of the solution increases. For example, if we have a solution with a certain normality and we dilute it to twice its original volume, the volume in the formula for normality will increase. ### Step 3: Apply the Dilution Concept Let’s denote: - \( N_1 \) = initial normality - \( V_1 \) = initial volume - \( N_2 \) = final normality after dilution - \( V_2 = 2V_1 \) = final volume after dilution Since the number of equivalents remains constant during dilution, we can set up the equation: \[ N_1 \times V_1 = N_2 \times V_2 \] Substituting \( V_2 \): \[ N_1 \times V_1 = N_2 \times (2V_1) \] ### Step 4: Solve for Final Normality From the equation, we can simplify: \[ N_2 = \frac{N_1 \times V_1}{2V_1} \] This simplifies to: \[ N_2 = \frac{N_1}{2} \] This shows that the final normality \( N_2 \) is half of the initial normality \( N_1 \). ### Step 5: Conclusion Thus, the only quantity that changes during the dilution of the solution is the normality. The normality decreases as the solution is diluted. ### Final Answer The correct answer to the question is that the **normality of the solution changes during dilution**. ---
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NARAYNA-SOLUTIONS & COLLIGATIVE PROPERTIES -EXERCISE : 1 (H.W)
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  5. Molarity of 0.1 N oxalic acids

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  6. Find the n factor of H(3) PO(4) in the following reaction. H(3) PO(...

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  7. The equivalent weight of MnSO(4) is half its molecular weight when it ...

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  8. I(2)+S(2)O(3)^(2-) to I^(-)+S(4)O(6)^(2-)

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  9. The equvivalent weight of CH(4) in the reaction CH(4)+2O(2)to CO(2)+2H...

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  10. M = molarity of the solution m = molality of the solution d = ...

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  14. The mole fraction of solvent in 0.1 molal aqueous solution is

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  15. A solution of 36% water and 64% acetaldehyde (CH(3)CHO) by mass. Mole...

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  18. Which of the following solutions will have the maximum lowering of vap...

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  19. The vapour pressure of water depends upon :

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