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Molarity of 1m aqueous NaOH solution [de...

Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

A

1 M

B

1.02 M

C

1.2 M

D

0.98 M

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The correct Answer is:
To find the molarity of a 1m aqueous NaOH solution with a density of 1.02 g/ml, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Molality**: - Molality (m) is defined as the number of moles of solute per kilogram of solvent. - Given that the molality of the NaOH solution is 1m, this means there is 1 mole of NaOH in 1 kg of water (solvent). 2. **Calculating the Weight of Solvent**: - Since the molality is 1m, the weight of the solvent (water) is 1 kg, which is equivalent to 1000 grams. 3. **Calculating the Weight of Solute (NaOH)**: - The molecular weight of NaOH can be calculated as follows: - Sodium (Na) = 23 g/mol - Oxygen (O) = 16 g/mol - Hydrogen (H) = 1 g/mol - Total molecular weight of NaOH = 23 + 16 + 1 = 40 g/mol. - Since we have 1 mole of NaOH, the weight of the solute (NaOH) is: - Weight of NaOH = 1 mole × 40 g/mol = 40 grams. 4. **Calculating the Total Weight of the Solution**: - The total weight of the solution is the sum of the weight of the solvent and the weight of the solute: - Total weight of solution = Weight of solvent + Weight of solute - Total weight of solution = 1000 g + 40 g = 1040 grams. 5. **Using Density to Find Volume of Solution**: - The density of the solution is given as 1.02 g/ml. - We can use the formula for density (Density = Weight/Volume) to find the volume of the solution: - Volume of solution = Total weight of solution / Density - Volume of solution = 1040 g / 1.02 g/ml = 1020.59 ml. 6. **Converting Volume to Liters**: - To convert the volume from milliliters to liters, we divide by 1000: - Volume in liters = 1020.59 ml / 1000 = 1.02059 L. 7. **Calculating Molarity**: - Molarity (M) is defined as the number of moles of solute per liter of solution: - Molarity = Number of moles of solute / Volume of solution in liters - Molarity = 1 mole / 1.02059 L ≈ 0.978 M. 8. **Final Result**: - The molarity of the 1m aqueous NaOH solution is approximately 0.98 M. ### Final Answer: The molarity of the 1m aqueous NaOH solution is **0.98 M**.

To find the molarity of a 1m aqueous NaOH solution with a density of 1.02 g/ml, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Molality**: - Molality (m) is defined as the number of moles of solute per kilogram of solvent. - Given that the molality of the NaOH solution is 1m, this means there is 1 mole of NaOH in 1 kg of water (solvent). ...
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