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A solution of 36% water and 64% acetalde...

A solution of 36% water and 64% acetaldehyde `(CH_(3)CHO)` by mass. Mole fraction of acetaldehyde is

A

`0.42`

B

`0.2`

C

`4.2`

D

`2.1`

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To find the mole fraction of acetaldehyde in a solution that is 36% water and 64% acetaldehyde by mass, we can follow these steps: ### Step 1: Assume Total Mass of the Solution Let the total mass of the solution be \( x \) grams. ### Step 2: Calculate the Mass of Each Component - Mass of water = \( 36\% \) of \( x \) = \( 0.36x \) grams - Mass of acetaldehyde = \( 64\% \) of \( x \) = \( 0.64x \) grams ### Step 3: Calculate the Number of Moles of Each Component To find the mole fraction, we need the number of moles of each component. **Moles of Acetaldehyde:** - Molecular weight of acetaldehyde (CH₃CHO) = \( 2 \times 12 + 4 \times 1 + 16 = 44 \) g/mol - Number of moles of acetaldehyde = \( \frac{\text{mass of acetaldehyde}}{\text{molecular weight}} = \frac{0.64x}{44} \) **Moles of Water:** - Molecular weight of water (H₂O) = \( 2 \times 1 + 16 = 18 \) g/mol - Number of moles of water = \( \frac{\text{mass of water}}{\text{molecular weight}} = \frac{0.36x}{18} \) ### Step 4: Calculate the Total Number of Moles Total number of moles in the solution = Moles of acetaldehyde + Moles of water \[ \text{Total moles} = \frac{0.64x}{44} + \frac{0.36x}{18} \] ### Step 5: Calculate the Mole Fraction of Acetaldehyde The mole fraction of acetaldehyde (denoted as \( X_{acetaldehyde} \)) is given by: \[ X_{acetaldehyde} = \frac{\text{moles of acetaldehyde}}{\text{total moles}} = \frac{\frac{0.64x}{44}}{\frac{0.64x}{44} + \frac{0.36x}{18}} \] ### Step 6: Simplify the Expression Since \( x \) is common in the numerator and denominator, we can cancel it out: \[ X_{acetaldehyde} = \frac{0.64/44}{0.64/44 + 0.36/18} \] ### Step 7: Calculate the Denominator To simplify the denominator: \[ \text{Denominator} = \frac{0.64}{44} + \frac{0.36}{18} \] Finding a common denominator (which is \( 44 \times 18 \)): \[ \text{Denominator} = \frac{0.64 \times 18 + 0.36 \times 44}{44 \times 18} \] ### Step 8: Calculate the Final Value Now, we can calculate the mole fraction: \[ X_{acetaldehyde} = \frac{0.64 \times 18}{0.64 \times 18 + 0.36 \times 44} \] Calculating the values: \[ = \frac{11.52}{11.52 + 15.84} = \frac{11.52}{27.36} \approx 0.42 \] ### Conclusion The mole fraction of acetaldehyde in the solution is approximately \( 0.42 \). ---

To find the mole fraction of acetaldehyde in a solution that is 36% water and 64% acetaldehyde by mass, we can follow these steps: ### Step 1: Assume Total Mass of the Solution Let the total mass of the solution be \( x \) grams. ### Step 2: Calculate the Mass of Each Component - Mass of water = \( 36\% \) of \( x \) = \( 0.36x \) grams - Mass of acetaldehyde = \( 64\% \) of \( x \) = \( 0.64x \) grams ...
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