Home
Class 12
CHEMISTRY
18 g glucose and 6 g urea are dissolved ...

`18 g` glucose and `6 g` urea are dissolved in `1 L` aqueous solution at `27^(@)C`. The osmotic pressure of the solution will be
a.`8.826 atm`, b.`4.926 atm`,c.`2.92 atm`, d.`4.42 atm`

A

0.492 atm

B

0.245 atm

C

4.92 atm

D

0.049 atm

Text Solution

Verified by Experts

The correct Answer is:
C

`pi V=(n_(1)+n_(2)).S.T`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS & COLLIGATIVE PROPERTIES

    NARAYNA|Exercise EXERCISE : 2 (C.W)|65 Videos
  • SOLUTIONS & COLLIGATIVE PROPERTIES

    NARAYNA|Exercise EXERCISE : 2 (H.W)|59 Videos
  • SOLUTIONS & COLLIGATIVE PROPERTIES

    NARAYNA|Exercise EXERCISE : 1 (C.W)|33 Videos
  • SOLID STATES

    NARAYNA|Exercise EXERCISE-4|18 Videos
  • SURFACE CHEMISTRY

    NARAYNA|Exercise EXERCISE - 4|22 Videos

Similar Questions

Explore conceptually related problems

9g of glucose and 3g of urea are dissolved in 1L of solution at 27^(@)C .The osmotic pressure of the solution will be

The Osmotic pressure of (M)/(10) solution of urea at 27^(0)C is ...... atm

Two solutions of glucose have osmotic pressure 1.5 and 2.5 atm ,respectively. 1 L of first solution is mixed with 2 L of second solution. The osmotic pressure of the resultant solution will be a. 2.62 atm , b. 6.12 atm ,c. 3.26 atm , d. 2.16 atm

The wt. of urea dissolved in 100 ml solution which produce an osmotic pressure of 20.4 atm,will be

The wt.of urea dissolved in 100ml solution which produce an osmotic pressure of 20.4 atm,will be

The osomotic pressure of a solution at 0^(@)C is 4 atm . What will be its osmotic pressure at 546 K under similar conditions? a. 4 atm , b. 9 atm ,c. 8 atm , d. 6 atm

x g of non-electrolytic compound (molar mass =200) is dissolved in 1.0 L of 0.05 M NaCl solution. The osmotic pressure of this solution is found to be 4.92 atm at 27^(@)C . Calculate the value of x . Assume complete dissociation of NaCl and ideal behaviour of this solution.

A solution is prepared by dissolving 0.6 g of urea (molar mass =60 g"mol"^(-1) ) and 1.8 g of glucose (molar mass =180g"mol"^(-1) ) in 100 mL of water at 27^(@)C . The osmotic pressure of the solution is: (R=0.08206L "atm"K^(-1)"mol"^(-1))

NARAYNA-SOLUTIONS & COLLIGATIVE PROPERTIES -EXERCISE : 1 (H.W)
  1. I(2)+S(2)O(3)^(2-) to I^(-)+S(4)O(6)^(2-)

    Text Solution

    |

  2. The equvivalent weight of CH(4) in the reaction CH(4)+2O(2)to CO(2)+2H...

    Text Solution

    |

  3. M = molarity of the solution m = molality of the solution d = ...

    Text Solution

    |

  4. Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 ...

    Text Solution

    |

  5. 0.1 gram mole of urea dissolved in 100 g of water. The molality of the...

    Text Solution

    |

  6. Density of 2.05 M solution of acetic acid in water is 1.02g//mL. The m...

    Text Solution

    |

  7. The mole fraction of solvent in 0.1 molal aqueous solution is

    Text Solution

    |

  8. A solution of 36% water and 64% acetaldehyde (CH(3)CHO) by mass. Mole...

    Text Solution

    |

  9. Incorrect statement is (K(H) = Henry's constant)

    Text Solution

    |

  10. Which of these curves represents Henry's law graph between partial pre...

    Text Solution

    |

  11. Which of the following solutions will have the maximum lowering of vap...

    Text Solution

    |

  12. The vapour pressure of water depends upon :

    Text Solution

    |

  13. Heptane and octane form an ideal solution. At 373 K, the vapour pressu...

    Text Solution

    |

  14. Choose the correct statement

    Text Solution

    |

  15. Isotonic solutions have :

    Text Solution

    |

  16. 0.1 M NaCl and 0.1 M CH(3)COOH are kept in separate containers. If the...

    Text Solution

    |

  17. Which one of the following statement is incorrect

    Text Solution

    |

  18. 18 g glucose and 6 g urea are dissolved in 1 L aqueous solution at 27^...

    Text Solution

    |

  19. A 5.25% solution of a substance is isotonic with a 1.5% solution of ur...

    Text Solution

    |

  20. 0.1 formal soluton of NaCl is found to be isotonic with 1.10% solution...

    Text Solution

    |