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5.85 g NaCl is dissolved in 500 ml of wa...

5.85 g NaCl is dissolved in 500 ml of water. The molarity is

A

`0.1`

B

`0.2`

C

`0.3`

D

`0.4`

Text Solution

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The correct Answer is:
To calculate the molarity of a solution, we can follow these steps: ### Step 1: Understand the formula for molarity Molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. The formula is: \[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \] ### Step 2: Convert the volume of the solution from milliliters to liters The volume of the solution is given as 500 mL. To convert this to liters, we divide by 1000: \[ \text{Volume in liters} = \frac{500 \text{ mL}}{1000} = 0.5 \text{ L} \] ### Step 3: Calculate the number of moles of solute To find the number of moles of solute (NaCl), we use the formula: \[ \text{Number of moles} = \frac{\text{Weight of solute (g)}}{\text{Molecular weight of solute (g/mol)}} \] The weight of NaCl is given as 5.85 g. Now, we need to find the molecular weight of NaCl: - The atomic weight of Sodium (Na) = 23 g/mol - The atomic weight of Chlorine (Cl) = 35.5 g/mol - Therefore, the molecular weight of NaCl = 23 + 35.5 = 58.5 g/mol Now, we can calculate the number of moles: \[ \text{Number of moles} = \frac{5.85 \text{ g}}{58.5 \text{ g/mol}} = 0.1 \text{ moles} \] ### Step 4: Calculate the molarity Now that we have the number of moles and the volume of the solution, we can calculate the molarity: \[ \text{Molarity} = \frac{0.1 \text{ moles}}{0.5 \text{ L}} = 0.2 \text{ M} \] ### Conclusion The molarity of the NaCl solution is 0.2 M. ---

To calculate the molarity of a solution, we can follow these steps: ### Step 1: Understand the formula for molarity Molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. The formula is: \[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \] ### Step 2: Convert the volume of the solution from milliliters to liters The volume of the solution is given as 500 mL. To convert this to liters, we divide by 1000: ...
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NARAYNA-SOLUTIONS & COLLIGATIVE PROPERTIES -EXERCISE : 2 (C.W)
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  9. The mass of oxalic acid crystals H(2)C(2)O(4).2H(2)O required to prepa...

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  16. A gaseous mixture contains 4.0g of H(2) and 56.0g of N(2). The mole fr...

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  17. Three statements are given about mole fraction (i) Mole fraction o...

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  18. Henry 's law constant for the solubility of N(2) gas in water at 298 K...

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