Number of milli equivalents of solute present in 250 ml of 0.1 M oxalic acid solution are

Options

A. 25
B. 50
C. 250
D. 125

Explanation

To find the number of milliequivalents of solute present in 250 ml of a 0.1 M oxalic acid solution, we can follow these steps:

### Step 1: Understand the Concept of Normality
Normality (N) is defined as the number of equivalents of a solute per liter of solution. For acids, the n-factor (number of replaceable hydrogen ions) is important to determine normality.

### Step 2: Determine the n-factor for Oxalic Acid
Oxalic acid (H₂C₂O₄) can donate 2 hydrogen ions (H⁺) when dissolved in water. Therefore, the n-factor for oxalic acid is 2.

### Step 3: Calculate Normality from Molarity
Normality can be calculated using the formula:
\[ \text{Normality (N)} = \text{Molarity (M)} \times \text{n-factor} \]
Given that the molarity of the oxalic acid solution is 0.1 M:
\[ \text{Normality} = 0.1 \, \text{M} \times 2 = 0.2 \, \text{N} \]

### Step 4: Use the Normality to Find Milliequivalents
The formula to calculate the number of milliequivalents (mEq) is:
\[ \text{Number of milliequivalents} = \text{Normality} \times \text{Volume of solution (in mL)} \]
Substituting the values we have:
\[ \text{Number of milliequivalents} = 0.2 \, \text{N} \times 250 \, \text{mL} \]

### Step 5: Perform the Calculation
\[ \text{Number of milliequivalents} = 0.2 \times 250 = 50 \, \text{mEq} \]

### Conclusion
The number of milliequivalents of solute present in 250 ml of 0.1 M oxalic acid solution is **50 mEq**.

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