The vapour pressure of water at 23^(@)C ...

The vapour pressure of water at `23^(@)C` is 19.8 mm of Hg 0.1 mol of glucose is dissolved in `178.2g` of water. What is the vapour pressure (in mm Hg) of the resultant solution?

`19.0`

`19.602`

`19.402`

`19.202`

Text Solution

Verified by Experts

The correct Answer is:

`(P_(0)-P_(s))/(P_(0))=(n_("glucose"))/(n_("glucose")+n_("water"))`

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