1.00 g of a non-electrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg `mol^(-1)`. Find the molar mass of the solute.

Options

A. 236 gm/mole
B. 256 gm/mole
C. 266 gm/mole
D. 274 gm/mole

Answer

B

Explanation

Substituting the value of various terms involved in equation we get,
`M_(2)=(5.12"K kg mol"^(-1)xx 1.00g xx 1000 g kg^(-1))/(0.40xx50g)=256 g mol^(-1)`
Thus, molar mass of the solute `= 256 g mol^(-1)`