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If 36.0 g of glucose is present in 400 m...

If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is

A

0.05 M

B

11.0 M

C

0.5 M

D

2.0 M

Text Solution

Verified by Experts

The correct Answer is:
C
`M=(w)/(GMW)xx(1000)/("V in ml")C_(6)H_(12)O_(6)=180`
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