If `N_(2)` gas is bubbled through water at `293 K`, how many millimoles of `N_(2)` gas would dissolve in`1 L` of water. Assume that` N_(2)` exerts a partial pressure of 0.987 bar. Given that Henry law constant for `N_(2)` at `293 K` is 76.48 kbar.

Options

A. `0.716`
B. `0.62`
C. `0.93`
D. `0.54`

Answer

A

Explanation

According to Henry.s law, `P_(N_(2))=K_(H), X_(N_(2))` i.e.,
`x_(N_(2))=(P_(N_(2)))/(K_(H))=0.987` bar/ `76.48xx10^(3)` bar = 12.9
`therefore` Number of moles = `12.9xx55.5` mol = 716 mol
`= 0.716` m moles