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The vapour pressure of water is 12.3 kPa...

The vapour pressure of water is `12.3 kPa` at `300 K`. Calculate vapour pressure of `1` molal solution of a solute in it.

A

`12.08k. P_(a)`

B

`1.208 k. P_(a)`

C

`2.4k. P_(a)`

D

`0.4 k. P_(a)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(p^(@)-p_(s))/(p^(@))=m.("(M.w) solvent")/(1000)`
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