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An ideal solution is obtained by mixing ...

An ideal solution is obtained by mixing `CH_(3)CHBr_(2)` and `CH_(2)Br - CH_(2)Br` in the ratio 2 : 1 `P_(CH_(3)CHBr_(2))^(@)=173, P_(CH_(2)BrCH_(2)Br)^(@)=127`. Thus total vapour pressure is

A

158

B

257

C

137

D

197

Text Solution

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The correct Answer is:
To solve the problem of finding the total vapor pressure of an ideal solution formed by mixing `CH3CHBr2` and `CH2BrCH2Br` in the ratio of 2:1, we can use Raoult's Law. Here is a step-by-step solution: ### Step 1: Identify the Components We have two components: - Component A: `CH3CHBr2` - Component B: `CH2BrCH2Br` ### Step 2: Given Data - Vapor pressure of pure `CH3CHBr2` (P0A) = 173 mmHg - Vapor pressure of pure `CH2BrCH2Br` (P0B) = 127 mmHg - Ratio of components A to B = 2:1 ### Step 3: Calculate Moles of Each Component Let the number of moles of `CH3CHBr2` be 2x and the number of moles of `CH2BrCH2Br` be x. ### Step 4: Calculate Total Moles Total moles (n_total) = moles of A + moles of B = 2x + x = 3x. ### Step 5: Calculate Mole Fractions - Mole fraction of A (xA) = moles of A / total moles = (2x) / (3x) = 2/3 - Mole fraction of B (xB) = moles of B / total moles = x / (3x) = 1/3 ### Step 6: Apply Raoult's Law According to Raoult's Law, the total vapor pressure (P_total) of the solution is given by: \[ P_{\text{total}} = P_{0A} \cdot x_A + P_{0B} \cdot x_B \] ### Step 7: Substitute Values Substituting the values we have: \[ P_{\text{total}} = (173 \, \text{mmHg}) \cdot \left(\frac{2}{3}\right) + (127 \, \text{mmHg}) \cdot \left(\frac{1}{3}\right) \] ### Step 8: Calculate Each Term Calculating each term: - For component A: \[ 173 \cdot \frac{2}{3} = \frac{346}{3} \approx 115.33 \, \text{mmHg} \] - For component B: \[ 127 \cdot \frac{1}{3} = \frac{127}{3} \approx 42.33 \, \text{mmHg} \] ### Step 9: Add the Contributions Now, add the contributions from both components: \[ P_{\text{total}} = 115.33 + 42.33 = 157.66 \, \text{mmHg} \] ### Step 10: Round Off Rounding off gives us: \[ P_{\text{total}} \approx 158 \, \text{mmHg} \] ### Final Answer Thus, the total vapor pressure of the solution is **158 mmHg**. ---
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NARAYNA-SOLUTIONS & COLLIGATIVE PROPERTIES -EXERCISE : 3
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  2. Isotonic solutions are those which have

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  3. An ideal solution is obtained by mixing CH(3)CHBr(2) and CH(2)Br - CH(...

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  7. The molar freezing point constant for water is 1.86 ^@C/ molal . If 3...

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  9. When 25 g of a non-volatile solute is dissolved in 100g of water, the ...

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  10. Each question contains STATEMENT-I(Assertion) and STATEMENT-2(Reason)....

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  11. 0.01 M solution of KCl and CaCl(2) are separately prepared in water. T...

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  12. 0.01 mole of a non-electrolyte is dissolved in 10 g of water. The mola...

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  13. In the following questions, more than one of the answers given may be ...

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  14. When mercuric iodide is added to the aqueous solution of potassium iod...

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  15. Which of the following represents the molarity of pure water?

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  16. Colligative properties

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  17. The molal freezing point constant for water is 1.86^(@)C//m. Therefore...

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  18. Boiling point fo chloroform was raised by 0.323K,when0.5143g of anthra...

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  19. Two bottles A and B contain 1M and 1m aqueous solution of sulphuric ac...

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  20. van't Hoff factor more than unity indicates that the solute in solutio...

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