What is the mass of the precipitate formed when 50 mL of 16.9% solution of `AgNO_(3)` is mixed with 50 mL of 5.8% NaCl solution?

Options

A. 7 g
B. 14 g
C. 28 g
D. 3.5 g

Answer

A

Explanation

wt of `AgNO_(3)rArr (16.9)/(2)g=.05` mol
Wt of NaCl `rArr (2.9)/(58.5)g`
`=(2.9)/(58.5)mol = (1)/(20)=0.5` moles
`{:(AgNO_(3),+,NaCl,to,AgCl,+,NaNO_(3)),(.05,,.05,,-,,),(-,,-,,.05mol,,):}`
wt of `AgCl rArr .05xx143.5g = 7.175g rArr 7g`