If `NaCI` is droped with `10^(-3)` mole of `SrCI_(2)` then number of cationic vacancies is

Explanation

Number of moles of cationic vacancies=100.
Mole of NaCl ` =10^(-3)`
`therefore ` Number of moles cationic vacancies per mole of NaCl ` = (10^(-3) )/(100) = 10^(-5)`
` therefore ` Total number of cationic vacancies= `10^(-5) xx N_0 = 6.02 xx 10^18`