The composition of a sample of wrustite is `Fe_(0.93)O_(1.00)`.Percentage of iron present in the form of iron (III) is nearly

Options

A. 85
B. 15
C. 7
D. 93

Answer

B

Explanation

Let the sample contains 93 iron ions and 100 oxide ions let no of `Fe^(3+) = x,` no of `Fe^(2+)` ions =93-x
we know total charge of a molecule should be zero
` therefore ` x(+3)+(93- x)(+2)+100(-2) = 0
` therefore ` x=14
% of ` Fe^(3+) = 14/93 xx 100 = 15.03 `