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In a structure, A atoms have fcc arrange...

In a structure, A atoms have fcc arrangement B atoms occupy all the tetrahedral sites and C atoms occupy half the octahedral sites. The formula of the compound is

A

`A_2B_2C_2`

B

`A_2B_4C`

C

`AB_2C`

D

`A_4B_2C`

Text Solution

Verified by Experts

The correct Answer is:
B
no of atoms in FCC=4=A(say)
T.V=8, O.V=4
no of atoms of B=8
no of atoms of C-4/2=2
`therefore ` formula ` A_4B_8C_2 = A_2B_4C`
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