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If the radius of K^(+) and F^(-) are 133...

If the radius of `K^(+)` and `F^(-)` are 133pm and 136pm respectively, the distance between `K^(+)` and `F^(-)` in KF is

A

269pm

B

134.5pm

C

136pm

D

3pm

Text Solution

Verified by Experts

The correct Answer is:
A
`r_(k+) + r_(F-) = 133 + 136`
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